If a Baseball is thrown straight upward from level ground with an intial velocity of $72$ ft/sec, its altitude $s$ (in feet) after $t$ seconds is given by $s = -16t^2 + 72t$. For what values of $t$ will the ball be at least $32$ feet above the ground?
I know the answer only which $1/2<t\leq4$ but i don't know the steps
hint: Solve: $-16t^2 + 72t \ge 32$.