Let $G$ be an infinitely generated group with Cayley graphs $X$. Define the edges of $X$ to be of length $1$. This makes $X$ a metric space.
Is it possible for $G$ to be quasi-isometric to a finitely generated (presented) group?
Any reference, suggestion or comments will be extremely helpful. Thanks in advance.
Certainly. For instance, if you take the generating set to be all of $G$, then $G$ is bounded, and so is quasi-isometric to any finite group. You can get examples where $G$ is quasi-isometric to an arbitrary finitely generated group $H$ by then taking a product with $H$.
(Note that the quasi-isometry class of $G$ depends very much on the set you choose to use as generators. This is in contrast with the finitely generated case, where all finite sets of generators give the same Cayley graph up to quasi-isometry. As far as I know, when $G$ is infinitely generated, there is typically no "canonical" class of generating sets which give quasi-isometric Cayley graphs analogous to the class of finite generating sets in the finitely generated case.)