Infinitely many moons, or one ring to bring them all, a limit to bind it?

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The Kanagy clan makes its home on a distant planet of mass $M_p$ with $k$ moons. Suppose the moons are identical with mass $m$. Furthermore, these moons share a common circular orbit on an orbital plane. The circular orbits are at distance $L$ from the center of the planet and the moons are evenly spaced.

  1. What is the speed $v(k)$ of the lunar orbits for a fixed, but finite, value of $k$?
  2. Suppose we hold $km=M_m$ fixed as $k \rightarrow \infty$, what is the limiting value of $\lim_{k \rightarrow \infty}v(k)$ in this context?

My ideal solution to this problem addresses $(1.)$ by vector analysis paired with the equation of motion for constant speed circular motion. Often cases $k=2$ or $k=3$ are given as homework problems in first semester university physics. I've found an expression for this in a previous attempt, but I'd rather not include it here for fear of biasing the reader. Next, the solution continues to $(2.)$, when I attempted to compute the limit directly it was rather involved. However, by intuition, I know the answer should easily derive from Newton's Law of Gravitation as follows: $$ \frac{M_mv^2}{L}= \frac{GM_mM_p}{L^2} \qquad \Rightarrow \qquad v = \sqrt{\frac{GM_p}{L}} $$

Given the preceding discussion, show show $v(k) \rightarrow \sqrt{\frac{GM_p}{L}}$ as $k \rightarrow \infty$. Alternatively, prove my intuition is incorrect.

Incidentally, I gave this as a bonus problem on a final exam in my university physics course. I had a student pretty well solve $(1.)$, but $(2.)$ I've not yet cracked. It is assumed that classical mechanics applies to this problem and any relativistic effects may be neglected.

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The centre of mass of the system is at the planet, which we can thus assume is stationary. If we number the moons $0$ to $k-1$, moon $0$ sees an angle $\theta_j = \dfrac{\pi}{2} - \dfrac{j \pi}{k}$ between moon $j$ and the planet, and the distance from moon $0$ to moon $j$ is $2 L \sin(j \pi/k)$. So the component in the direction of the planet of the gravitational acceleration of moon $0$ due to moon $j$ is $\cos(\theta_j) G m/(2 L \sin(j \pi/k))^2 = G m/(4 L^2 \sin(j \pi/k))$. The net gravitational acceleration (directed toward the planet) due to all the other moons is then $$ \sum_{j=1}^{k-1} \dfrac{G m}{4 L^2 \sin(j \pi/k)} = \sum_{j=1}^{k-1} \dfrac{G M_m}{4 k L^2 \sin(j \pi/k)} > \sum_{j=1}^{k-1} \dfrac{G M_m}{4 L^2 \pi j}$$ But that goes to $+\infty$ as $k \to \infty$. So we must also have $v(k) \to \infty$.