I was bored and started thinking of fractals and decided I scribbled what I thought could be one.
$$a_{i+1} = (a_i - b_i) / c_i $$ $$b_{i+1} = (b_i - c_i) / a_i $$ $$c_{i+1} = (c_i - a_i) / b_i $$
I was just wondering if there was any information on this or what type of fractal this could be? I like the look of each layer as it develops.
I inputted into a vba program and got this as one of the layers of this fractal.
Red lines show are where the function at one point gave a div by zero error everywhere else is roughly how fast it goes to infinity.
For those who have excel and know how to use its code here is the code I wrote to generate this. Just note not to run this with any conditional formatting it will slow to a crawl and never complete.
Sub main()
Application.EnableEvents = False
Application.DisplayAlerts = False
Dim x, y, z As Double
For x = -100 To 100
For y = -100 To 100
For z = -100 To 100
SpeedToInfinity = Itterate(x / 100, y / 100, z / 100)
ThisWorkbook.Worksheets(1).Cells(y + 101, z + 101) = SpeedToInfinity
DoEvents
Next
Next
abc = 1 ' set a break point here.
Next
Application.EnableEvents = True
Application.DisplayAlerts = True
End Sub
Function Itterate(a As Double, b As Double, c As Double)
Dim newA, newB, newC As Double
Dim counter, counterMax As Integer
counterMax = 200
On Error GoTo ErrorHit
For counter = 0 To counterMax
newA = (a - b) / c
newB = (b - c) / a
newC = (c - a) / b
a = newA
b = newB
c = newC
Next
ErrorHit:
Select Case Err.Number
Case 11: 'div by zero
counter = counter * -1
Case 0:
End Select
Itterate = counter
End Function

Note that only the direction of the $(a b c)$ vector matters, as a common factor will be eliminated after each iteration:
$$\begin{pmatrix} a \\ b \\ c \end{pmatrix} := \begin{pmatrix} (a - b) / c \\ (b - c) / a \\ (c - a) / b \end{pmatrix} = \begin{pmatrix} (ka - kb) / kc \\ (kb - kc) / ka \\ (kc - ka) / kb \end{pmatrix}, \forall k \not= 0$$
So it is convenient to consider the starting points on the unit sphere, using an appropriate projection to 2D. I used stereographic projection here: https://shadertoy.com/view/3s23DV
The darkest lines on the edges of an octahedron correspond to division by zero at the first iteration. Then there are slightly less dark lines for division by zero at subsequent iterations.
You can hopefully see the structure has a 3-fold rotational symmetry about an axis with poles at near-center bottom left and top right of the image, and 2-fold point reflection symmetry about the center of the sphere.
(Pre)periodic cycles (that don't get too large) would certainly be bright in the image, so consider those: Wolfram Alpha gives fixed points $(a_0≈2.53209, b_0≈-0.879385, c_0≈1.3473)$ and rotations thereof. So the poles should be at the normals of the plane formed by those 3 fixed points: let $u = (a_0, b_0, c_0), v = (b_0, c_0, a_0), w = (c_0, a_0, b_0)$ then the poles should be in the directions $\pm (u - v) \times (w - v)$. By a symmetry argument I think that works out as $\pm(1,1,1)$ but I need to double-check this.
Because only the direction matters, solutions to the family of equations $$\begin{pmatrix} a \\ b \\ c \end{pmatrix} = k \begin{pmatrix} (a - b) / c \\ (b - c) / a \\ (c - a) / b \end{pmatrix}$$ also end up in a cycle of period $1$ (with preperiod $1$). AFAICT the solution should vary smoothly with $k$ not passing through $0$, with $3$ rotationally symmetric branches times $2$ signs for $k$, so perhaps it could be instructive to plot these $6$ curves. (I have no time to try that today, but may revise this answer at a later date.)