Given the equivalence relation on N aRb $\leftrightarrow $ a and b are both even or odd, given a function $f: N\rightarrow\{x,y\}$ with $f(n)=x$ if n is even and $f(n)=y$ if n is odd exists an injective function from $N/R$ to $\{x,y\}$? Can I use a homeomorphism theorem?
2026-03-30 16:22:16.1774887736
Injective function from N/R to {x,y}
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You need to show that $\Bbb N/R$ has only two elements. Then you can just create an injective function by taking one to $x$ and the other to $y$.