Inner product that snipes out the zero element

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Say I have a complex Hilbert space, with the typical inner product:

$$ \langle u,v \rangle=u^\dagger v $$

The inner product for the zero element is also zero : $\langle 0,0 \rangle=0$

Say, I am to call the zero state an 'undesirable' state (it produces non-normalizable states for a wave-function, for instance). Can I remove it from the inner product? Can I define the inner product as follows:

$$ \langle u,v \rangle=\begin{cases} \nexists & \text{if } u=v=0 \\ u^\dagger v & \text{otherwise} \end{cases} $$

Quantum Mechanics seems to like it --- this is basically the inner product of allowed physical states. Is there any reason mathematicians don't like that? Is the space still a Hilbert space. If not what is it?

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Of course you can define it this way. In mathematics, we may define anything whichever way we like. The question you should be asking is: does this definition make anything I'm doing easier?

We do not need ontological commitment to the entities of our models, and there's really no reason to try to "pare down" a model to only entities that seem "real," unless you can do it in a way that systematically avoids the need to manually handle edge-cases.

As far as I can tell, this does the opposite of that. It doesn't systematically change anything; all it does is introduce the need to propagate a bunch of extra conditions through all of the proofs. Anyone using the mathematics to actually describe a thing will be able to prune the nonphysical entities post-hoc - there's no need to tediously carry the caveats through each step of the math when they don't change the logical structure of the arguments.