$\int \frac{dZ}{Z^2-A^2}$ vs $\int \frac{dZ}{A^2-Z^2} $

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Solving the two integrals in the topic above using partial fractions gave the following result:

$$\int \frac{dZ}{Z^2-A^2} = \frac{1}{2A}\ln{\frac{Z-A}{Z+A}}+C.....eqn(1)$$

and

$$\int \frac{dZ}{A^2-Z^2} = \frac{1}{2A}\ln{\frac{A+Z}{A-Z}}+C.....eqn(2)$$

However I also noticed that I can express a relationship between the two integrals as thus:

$$\int \frac{dZ}{Z^2-A^2} = -\int \frac{dZ}{A^2-Z^2}.....eqn(3)$$

If the above eqn(3) is true, then it means we can further solve eqn(3) to give thus:

$$\int \frac{dZ}{Z^2-A^2} = -[\frac{1}{2A}\ln{\frac{A+Z}{A-Z}}+C_1] $$

Which simplifies into:

$$\int \frac{dZ}{Z^2-A^2} = \frac{1}{2A}\ln{\frac{A-Z}{A+Z}}+C].....eqn(4)$$

But looking at eqn(1) and eqn(4), they both appear to be different. What am I missing?