Integral from inverse Fouriertransform of 1/(1+p^2)^2

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In a calculation I end up with the following integral

$$\int_0 ^\infty \frac{p \sin (pr)}{(1+p^2)^2}dp , $$ could someone give me a hint how to evaluate this one?

(This integral comes from the inverse Fourier transform of the function $\frac{1}{(1+p^2)^2}$.)

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Simplification thanks to partial integration :

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