How do i solve this one using exponential function? should i bring up x^2? $$\int\frac{2^{\frac{1}{x}}}{x^2}dx$$
2026-04-13 10:00:28.1776074428
Integral of exponential function?
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$$t=(1/x)$$,$$-dt=\frac{dx}{x^2}$$$$\int2^tdt=\frac{2^t}{\ln2} +C$$