$$\int\frac{1}{(x^2 +4x+9)}\,dx$$ Just playing around with this integral ,is it possible to do this integral by trig substitution? I would personally just go by completing the square then doign u-sub, but is trig sub possible here?
2026-04-02 23:38:26.1775173106
integral substitution not by u-sub
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$$\int\frac{1}{(x^2 +4x+9)}\,dx =\int\frac{1}{(x+2)^2 +5}\,dx $$
The trig substitution $$ (x+2)=\sqrt 5 \tan(t)$$ would do.