Integral w.r.t. a Martingale

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Consider the stochastic integral

$$ Z_t = 1+\int_0^tZ_{s^{-}}\,dX_s $$

where $X$ is a Martingale. In the textbook by Shreve (see here pages 493-493) it is said that since $Z_{s^{-}}$ is left-continuous and the integrator $X$ is a martingale then $Z_t$ is a martingale. I cannot figure out why this should be the case, any suggestions?

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In fact, one can show that for any p > 1, and bounded predictable integrand, the stochastic integral preserves the space of p-integrable martingales. If your process is a bounded left-continuous process, then it holds. You could have more info on the following link : https://almostsure.wordpress.com/2010/04/06/the-burkholder-davis-gundy-inequality/