Find the integral of the form $dy∧dz+dz∧dx$ over the boundary of the standard cube in $R^3$.
My thought: consider $\omega =y dz+ z dx$ so that $d\omega =dy∧dz+dz∧dx$
That is by Stokes, we have $$ \int_{I^3} d\omega =\int_{\partial I^3} \omega $$ I don't know how to proceed, any help would be appreciated.