integrate $\int_0^1 \int_{1+y}^{2y} \int_z^{y+z} z\, dx\,dz\,dy$

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My solution:

Integrate w.r.t $x$ and get $zx$, after inserting the boundaries of $x$ I get $zy$.

Integrate w.r.t $z$ and get $y \frac{z^2}{2}$, after inserting the boundaries of $z$ I get $\frac{3y^3-2y^2-y}{2}$.

Integrate w.r.t $y$ and get $\frac{3y^4}{8} - \frac{y^3}{3} - \frac{y^2}{4}$, after inserting the boundaries of $y$ I get $\frac{-5}{24}$.

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Yes, your answer is correct. You have explained every step very clearly. Good Job!