Integrating by Parts $\int\limits^{2}_{0}pydy$ - A calculation related to flowrate.

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Happy new year everyone!

I have a question that I struggle related to integration by parts.

Suppose I'm going to solve the following using integration by parts. $$\int\limits^{2}_{0}pydy$$ Where $p$ is a function of $y$.

I know the formula for integration by parts for definite integrals:
$$\int\limits_{a}^{b}udv=uv\Big|_{a}^{b} - \int\limits_{a}^{b}vdu$$

Thus I'm considering: $$u=y \text{ and } dv=pdy$$

This gives me:
$$du=dy \text{ and } v=\int pdy$$

Now by substituting into the original formula,
I have:
$$\begin{align} \int\limits^{2}_{0}pydy &= \left(y\int pdy\right)\Big|_{0}^{2} - \int\limits_{0}^{2}(\int pdy)dy \end{align}$$

I also have the function $Q(y)$ where, $$Q(y) = \int\limits_{0}^{y}p(t)dt$$

Now this is the place I find it confusing to substitute the limits of the integral.

And my goal is to write the integration by parts equation in terms of this function $Q(y)$ because $Q(y)$ is actually a two-dimensional flow rate where we have $Q(0)=0$, $Q(2)=k$ a known value.

Appreciate your help