I'm stuck with the bellow integral and couldn't find any solution, If anyone has an idea how to continue I'll be very grateful.
(1)\begin{equation} \int_{0}^{2\pi} e^{a\cdot\sin2\theta+b\cdot\cos(\theta-\mu)}d\theta \end{equation}
I know that
(2) $$\int_{0}^{2\pi} e^{a\cdot\sin\theta+b\cdot\cos\theta}d\theta={2\pi I_0(\sqrt{a^2+b^2})}$$
but couldn't find any way to get from (1) to (2)
Thank you very much!