Does anyone know how to solve: $$(2x^2-xy)dx-(y^2+xy)dy=0$$ I solved that $$\frac{dy}{dx} = \frac{(2x^2-xy)}{(y^2+xy)}$$
Then, I substituted $vx$ for $y$ and found that $$-\frac{dx}{x}=\frac{(v^2+v)dv}{(v^3+v^2+v-2)}$$ However, I don't know how to approach the integration in the right side. I even checked Symbolab and integration calculator, but most of these online resources weren't able to provide any aid in this problem.
Please help!