I am a bit lost how to proceed this integration (I got a recommendation to use substitution here) with goniometric functions in here. I know the correct result, but still can't determine it.
2026-03-29 22:15:18.1774822518
Integration goniometric functions with using substitution
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Simply set $u = \text{tg} x$. Then $du = \sec^2 x \, dx$ and the integral reduces to $\int u \, du$.