Integration over one point set

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Suppose we have a continuous function $f:S^2\rightarrow \mathbb{R}$ on the standard sphere. What value is given for the following integral $$\int_{\lbrace p\rbrace }f(x) \text{d$vol_{\lbrace p\rbrace}$(x)},$$

where $p\in S^2$ is any fixed point and d$vol_{\lbrace p\rbrace }$(x) is the "Riemannian volume element"? I am not sure what exactly the definition of the Riemannian volume element is in the above context, since the manifold consists of one point only. Is it just $\int_{\lbrace p\rbrace }f(x) \text{dvol(x)}:=f(p)$?

Edit: The Riemannian volume element d$vol_{\lbrace p\rbrace }$(x) is most likely meant as the Riemannian volume element of the Riemannian manifold $\lbrace p \rbrace$. (See my comment below).

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As far as I know,

$\int_{ \lbrace P \rbrace } f(x)dvol_{ \lbrace P \rbrace }(x) = 0$

But for $\delta(x)$ to be the impulse function,

$\int_{ \lbrace P \rbrace } f(x)\delta(x)dvol_{ \lbrace P \rbrace }(x) = f(P)$