Is it possible to evaluate the multidimensional integral below, assuming spherical coordinates, without any additional information other than the facts that there is no dependence on $\phi_p$, $\phi_q$, $\phi_{\text w}$, and $\{a, b_1, b_2, m, p, q,{\text w},\theta_{\text{ anything}}\}\,>0$ ?
Note that $\theta_{p\,q}$ is the angle between vectors ${\bf p}$ and ${\bf q}$, and similarly for $\theta_{{\text w}\,q}$, $\theta_{p\,{\text w}}\,$; and $|{\bf p}|\,\equiv\,p$ etc.
$\displaystyle{\int_{0}^{\pi}\sin(\theta_{\text w})\,d{\theta}_{\text w}\int_{0}^{\infty}{\text w}^{2}d{\text w} \,\int_{0}^{\pi}\sin(\theta_{p})d{\theta}_{p}\int_{0}^{\infty}p^{2}d{p} \,\int_{0}^{\pi}\sin(\theta_{q})d{\theta}_{q}\int_{0}^{\infty}q^{2}d{q}\\ \frac{\left[{\text w^{2}}\,+\,m^{2}\right]}{\left[{\text w}^{2}\,+\,a^{2}\right]^{4}\left[{p}^{2}\,+\,a^{2}\right]^{2}\left[{q}^{2}\,+\,b_{2}^{2}\right]^{2}}\cdot\\ \frac{1}{\bigl[p^{2}+q^{2}+{\text w}^{2}-\,2\,p\,q\,\cos(\theta_{p q})+2\,p\,{\text w}\,\cos(\theta_{p {\text w}})-2\,q\,{\text w}\,\cos(\theta_{{\text w} q})+b_{1}^{2}\bigr]}}$