$a,b > 0$ and $c<d$
Show that $g(x) = \displaystyle \frac{a}{(x-c)^4} + \frac{b}{(x-d)^7}=0$ has at least a solution in $(c,d)$
I defined
$\lim\limits_{x\searrow c}g(x)=+\infty$
$\lim\limits_{x\nearrow d}g(x)=-\infty$
I don't know if the limits are just enough for the proof, or is there something else?
The limits are almost enough. You just need to finish up by saying that the limits imply the existence of positive/negative points, and the continuity of the function on the interval $(c, d)$ implies a zero is contained in the interval (by the Intermediate Value Theorem).