Interpretation of group elements in Cayley graph vs matrix representation

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Recently when learning group theory, I came across Cayley graphs and upon looking at how can be labelled, I was confused.

Take the $D_4$ dihedral group for example. From wikipedia there is a Cayley graph of $D_4$ in which the element $a$ corresponds to a rotation of $\pi/2$ clockwise, and $b$ corresponds to a reflection about a vertical axis. The graph also suggests that $ab$ corresponds to the rotation $a$ followed by the reflection $b$, and this has caused me some confusion because I would think that a rotation then a reflection would instead correspond to $ba$ rather than $ab$.

Cayley graph of $D_4$

I think this because the matrix representation of $D_3$ has a rotation of $\pi/2$ clockwise given by $$R=\begin{pmatrix}0 & 1\\\ -1 & 0\end{pmatrix}$$ and a reflection along a vertical axis is $$S=\begin{pmatrix}-1 & 0\\\ 0 & 1\end{pmatrix}$$ When doing the multiplication, we get $$RS=\begin{pmatrix}0 & 1\\\ 1 & 0\end{pmatrix}$$ which corresponds to a reflection about the axis $y=x$, which geometrically is a reflection about a vertical axis then a rotation $\pi/2$ clockwise. Note that this is not a rotation and then a reflection which the Cayley graph suggests with $ab$.

So it seems like the matrix representation has transformations applied from right to left, and in the Cayley graph, transformations are applied from left to right. What's the reason for this difference?

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Historically we defined the composition $f(g(x)) = (g \circ f)(x)$ so that reading from left to right we would apply $g$ first, then $f$. However this gets confusing so the convention that $f(g(x)) = (f \circ g)(x)$ is also in use. This can cause some side switching when we consider an operation as a multiplication in a group or as a function acting on a set depending on the author. However the left-group action is more common which is consistent with column vector standard for a the matrix representation.

So if we call $v$ the vertex vector then $RSv$ would transform this vector and simply by writing $R(Sv)$ we can see that the reflection should be applied first, then the rotation. When studying the symmetric group on $n$ letters you will also be applying transformations from the right to the left to understand the action.