Problem: Let $L$ be a set of $n$ lines in the plane in general position, that is, no three of them containing the same point. The lines of $L$ cut the plane into $k$ regions. Prove by induction on $n$ that this subdivision of the plane has $\binom{n}{2}$ vertices, $n^2$ edges, and $\binom{n}{2} + n + 1$ cells.
I don't need help solving this problem, I just need help interpreting it. What does it mean that the plane is cut into $k$ regions? I thought that the number of regions was determined by $n$. Also, what's the point of the $k$ if we're not proving anything about it?
Finally, what is meant by cells? Also, are edges the finite segments between intersections?
I tried the case for $n=3$ and I think i found the correct interpretation, but you should do it yourself to confirm. It seems that they do not allow for parallel lines, in which case you are right that the $k$ in "$k$ regions" is not relevant.
"Vertices" is clear: a vertex is a point where a pair of lines intersect
"Edges" are any piece of line: a finite line segment between vertices, an infinite ray emanating from a vertex, or a whole line (in the case of $n=1$)
"Cells" means any face created by the lines. In other words, a region of the plane is a cell if you can draw a continuous path between any 2 points in the cell without crossing a line