Intuition behind orthogonal decomposition of $L^2(\mu)$

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We are working with the Hilbert space $L^2(\mu)$, such that $\mu(X)<\infty$.

If $M$ is the subspace of constant functions, define $M^\perp$ both formally and "intuitively". (This is a homework problem). My problem is the intuitive description part.

We are told that

$$M := \{g \in L^2(\mu) : g(x) = c \in \mathbb{R}, \ \forall x \in X\}$$ Therefore, if we want the orthogonal complement,

$$M^\perp= \{f \in L^2(\mu) : \langle f,g\rangle=0, g \in M\}$$

Therefore, for any function $f \in M^\perp$, and real constant $c$

$$\langle f, c\rangle = 0 = \int_X cf \ \mathrm{d} \mu = c \int_X f \ \mathrm{d} \mu$$

Thus, it follows that

$$M^\perp = \left\{f \in L^2(\mu) : \int_X f \ \mathrm{d} \mu = 0 \right\}$$

But, I don't understand what would an intuitive definition/description would be in this case.