Intuition for why the superposition of many independent renewal processes is well-approximated by a Poisson process

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I’m trying to get an intuition for why the superposition of independent renewal processes in equilibrium converges – locally, on small timescales – to a Poisson process. (I mean a general renewal process; that the superposition of Poisson processes yields a Poisson process is a special case of this.)

Let $(N_i(t))_{i=1\ldots n}$ be $n$ independent renewal processes with i.i.d. interarrival times $X$, with CDF $F$ and density $f$, and set $μ := \mathbb{E}(X)$. Suppose the interarrival time $X$ is not arithmetic. I’m interested in the interarrival time of the “merged” process $N(t) = \sum_{i=1}^n N_i(t)$.

Here is what I know:

A key result in renewal theory is that in equilibrium, the excess life of the process $N_i$ has CDF:

$$\mathbb{P}(E(t) \le y) \to \frac{1}{μ}\int_0^y [1-F(x)]\,dx$$

Therefore, in the superposition $N(t)$ in equilibrium, by taking the minimum over $N$ realizations of $X$, the interarrival time $Y$ has CDF:

$$\begin{aligned} \mathbb{P}(Y \le y) &= 1 - \left(1-\frac{1}{μ}\int_0^y[1-F(x)]\,dx\right)^n \\ &= 1-\left(\frac{1}{μ}\int_y^\infty[1-F(x)]\,dx\right)^n \\ \end{aligned}$$

Based on the references below, $N(t)$ converges to a Poisson process for $n\to\infty$, so for large $n$ it should be “approximately Poisson”, so that the interarrival time $Y$ should be “approximately exponential”.

In other words, I think the following holds, but I’d appreciate your help explaining why this seems to hold or how fast the convergence happens:

$$\mathbb{P}(Y \le y) \approx 1-e^{-λy}$$

Based on a few numeric examples I tried out, it seems $λ \approx \frac{n}{μ}$.

References

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I think I acquired some intuition now, sharing what I learned. They key is to realize that in general, the superposition of many independent renewal processes does not converge to a Poisson process globally, just locally.

Feller Vol II 1968, XI.4 example (a), covers this topic and puts it thus:

We require, roughly speaking, that the renewal epochs of each individual renewal process are extremely rare so that the cumulative effect is due to many small causes.

The paper Superposition of many independent spike trains is generally not a Poisson process has a good explanation why one cannot in general hope to obtain a Poisson process globally, only on short time scales:

Put differently, if the single spike train $x_n(t)$ is sparse enough compared to the time window $T$ for which we consider the superposition of point processes […] then on this short time scale $T$, the process $X(t)$ constitutes a Poisson process. This amounts in the frequency domain to ignoring the low frequency range[.]


Intuition: For a distribution function $F$ of the interarrival time, in many well-behaved cases, $F(ε)\approx 0$ for $ε \ll μ$. Then $1-F(ε) \approx 1$, and therefore:

$$\begin{aligned} \mathbb{P}(Y>ε) &= \left(1-\frac{1}{μ}\int_0^ε [1-F(x)]\,dx\right)^n \\ &\approx \left(1-\frac{ε}{μ}\right)^n \\ &\approx e^{-εnμ^{-1}} \end{aligned}$$

As an example, consider renewals with a Gamma density and $α=100, β=200$, so that $μ=\frac{1}{2}$:

Illustration