renewal equation for $\sim U(0,1)$ interarrivals should be
$m(t)=t+\int_0^t{m(t-s)f(s)ds}$
how can this be solved?
can I make substitution $y=t-s$ to get
$m(t)=t+\int_0^t{m(y)f(y)dy}$ if all I know is that t>1 ?
What will make this substitution valid?
You need to correctly do the substitution $y=t-s$ to get
$$m(t)=t+\int_{-\infty}^{t}m(y)dy$$
And now differentiate in $t$:
$$m'=1+m$$
Which you can solve easily. You'll need an initial value of $m(t)$ which you can deduce from the limit condition $m(t)/t$ for renewal processes.
By the way you should check to see if you've written things down right. There should be a density function inside the integral: $m(t-s)f(s)$ and the density is 0 when $s>1$.