I am trying to project estimated internal resistance of a battery.
We know that the internal resistance approximately halves as the capacity of the battery doubles.
For example... A 2AmpHour cell has 8milliOhms of resistance A 4AmpHour cell has 4milliOhms of resistance A 8AmpHour cell has 2milliOhms of resistance
What i wonder is how i might put this into a calculation.
I have tried a search, and i do suspect an answer might exist but half the problem might be i am not sure of the terminology.
My appreciation in advance of your reply.
Let $b$ be the capacity in ampere hours and $r$ be the resistance. Then $br = 16, r = 16/b, b = 16/r$.