Write down the derivative of the function y=x^3 - 1: 3x^2
Make x the subject and hence find dx/dy: 1/3(y+1)^-2/3
Show that dy/dx * dx/dy = 1
How does the x and y possibly cancel out?
It seems like a very straightforward question but what do i do?
Write down the derivative of the function y=x^3 - 1: 3x^2
Make x the subject and hence find dx/dy: 1/3(y+1)^-2/3
Show that dy/dx * dx/dy = 1
How does the x and y possibly cancel out?
It seems like a very straightforward question but what do i do?
Well, we have
$$\frac{dx}{dy}=\frac13(y+1)^{-2/3}=\frac13((x^3-1)+1)^{-2/3}=\frac13x^{-2}$$
Then can you show the product is one?