Is it possible to find a continuous bounded real function $f$ such that $\mathcal Lf(z)=\exp(-z^2)$ where $\mathcal Lf(z)=\int_0^{+\infty} e^{-tz}f(t)dt$ ?
I don't find anything in the tables...
Is it possible to find a continuous bounded real function $f$ such that $\mathcal Lf(z)=\exp(-z^2)$ where $\mathcal Lf(z)=\int_0^{+\infty} e^{-tz}f(t)dt$ ?
I don't find anything in the tables...
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