IT is asked to find the inverse Laplace transformation of
$$\frac{7s-6}{s^2-s-6}$$
Writing it with partial fractions
$$\frac{7s-6}{s^2-s-6} =\frac{4}{s+2}+\frac{3}{s-3}$$
Ive found that the function that have this Laplace transformation is
$$4 \exp(-2t)+3\exp(3t)$$
But the given answer was
$$\frac{8}{3}\exp(2t)+\frac{13}{3}\exp(-t)$$
I can't see the equivalency. Maybe the answer is wrong .
Thanks!