Inverse Laplace transform to $e^{-s^2}$

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Does $\mathcal{L}^{-1}\{e^{-s^2} \}(t) $ or equivalently, $$f(t)=\dfrac{1}{2\pi i}\int_{\sigma - i\infty}^{\sigma+i\infty} e^{st}e^{-s^2} ds$$ exist under closed form?