I have taken this question from Zhang, Fuzhen. Linear Algebra (Johns Hopkins Studies in the Mathematical Sciences)
Assuming that all matrix inverses involved below exist, show that
$(A + iB)^{-1} = B^{-1} A(A + AB^{-1} A)^{-1} − i(B + AB^{-1} A)^{-1}.$
I can simplify the right hand side to obtain $(A + B)^{-1} − i(B + AB^{-1} A)^{-1}$. The hint in the answer key says multiply the right hand side by $(A + iB)$ to verify. But at this point everything is an inverse of the sum. Is there a way to move forward other than using a formula like in this question: Inverse of the sum of matrices?.
There seems to be a typo. The correct formula should be $$ (A+iB)^{-1}=(B^{-1}A-iI)(B+AB^{-1}A)^{-1}. $$ To verify this, multiply the candidate inverse from the left with $A+iB$ to obtain $$ (A+iB)(B^{-1}A-iI)(B+AB^{-1}A)^{-1} =(AB^{-1}A-iA+iA+B)(B+AB^{-1}A)^{-1}=I. $$