Lets say I have a matrix: $$\left[\begin{array}{cc} 2 & 4 \\ 3 & 7 \\ \end{array}\right] $$
And my maximum range value is $10$, how would I go about creating another matrix that inverts those values? So that the matrix would end up looking like:
$$\left[\begin{array}{cc}
8 & 6 \\
7 & 3 \\
\end{array}\right]
$$
In algebraic form?
Based on your example, it looks like you're asking the following:
The answer to that question is: "Yes, but it isn't necessarily very interesting." Let $J$ be the $2\times 2$ matrix of $1$s. Then for any $m>0$ and any $2\times 2$ matrix $A$ with entries between $0$ and $m$ (inclusive), the matrix $m\cdot J-A$ does the trick (where $m\cdot J$ indicates scalar multiplication by $m$).
If that's not what you were trying to ask, then please clarify. It might help if you told us what led you to ask this question, too.