Is a compacthypersurface $S \subset \mathbb{R}^n$ a "conformally compact Einstein manifold"?

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If $S$ is a hypersurface in $\mathbb{R}^n$ (like a sphere) then is $S$ a "conformally compact Einstein manifold"?

It's a compact manifold. According to the wiki, it is a conformal manifold if it is equipped with an equivalence class in which two metrics $g$ and $h$ are equivalent iff $h=\lambda^2 g$ for $\lambda:S \to \mathbb{R}$ smooth.

An Einstein manifold I find difficult to understand since I don't understand Ricci tensors.