can you tell me is $(\bigtriangledown . A)B = (B.\bigtriangledown )A$?
I know that $(\bigtriangledown. \omega)r = (r.\bigtriangledown) \omega$
there is a problem, given that velocity v=r×ωv=r×ω then prove that ω=(1/2)▽×vω=(1/2)▽×v while proving this i got (▽.ω)r=(r.▽)ω(▽.ω)r=(r.▽)ω so i was thinking wther this is general axiom for any 2 vectors A and B?