It seems that the answer is no, but I'm struggling to think of a proper example.
Would I be best trying to think of a closed set whose complement is open?
It seems that the answer is no, but I'm struggling to think of a proper example.
Would I be best trying to think of a closed set whose complement is open?
$\mathbb{Q}$ is not closed in $\mathbb{R}$ (with the usual metric)