Is $\exp(x-x_0) = \exp(x)\cdot \exp(-x_0)$?

Question

I try to do the integral of $\exp(x-x_0)$. However, I am not sure that if it is true that $$\exp(x-x_0) = \exp(x)\cdot\exp(-x_0)$$ I don't think it is $$\dfrac{\exp(x)}{\exp(x_0)}$$

Answer 1

$$\exp(x-x_0)= \exp(x)\exp(-x_0)= \frac{\exp(x)}{\exp(x_0)}$$