Is $f*\mu(x)=\int f(xy)dy$?

41 Views Asked by At

I am only recently familiarizing myself with basic harmonic analysis so pardon me if my question seems odd. I have a locally compact abelian topological group $G$. For $f:G\rightarrow \mathbb{C}$ I have the definition $$f*\mu(x)=\int \Delta(y^{-1})f(xy^{-1})dy$$ And I have the identity $$\int f(x^{-1})\Delta(x^{-1})dx=\int f(x)dx$$ So with these two, wouldn't we get $f*\mu(x)=\int f(xy)dy$ ?