I have to make or deny proof for : $\exists X \forall Y \exists Z .(X\subseteq Y \cap Z) $
Is the proof by saying that $\emptyset \subseteq All$ and so $X = \emptyset$
enough?
2026-03-26 19:20:11.1774552811
Is following proof of $\exists X \forall Y \exists Z .(X\subseteq Y \cap Z) $ valid?
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