Is $\frac{\partial}{\partial{t}}(\nabla\times H) = \nabla \times \frac{\partial H}{\partial t}$?

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While trying to prove a particular equation using Maxwell's equations in electromagnetic theory, there is a step in my textbook that says

$$\frac{\partial}{\partial{t}}(\nabla\times H) = \nabla \times \frac{\partial H}{\partial t}$$

Why is this true? Is it because of the Clairaut's theorem on partial derivatives?