Is it okay to say that a function that's non-continuous at a point is continuous on its domain?

Question

I was watching a video on the main continuity theorem, and the following slide came up:

Even though $f(x) = \sin \frac{1}{x}$ is not continuous at $x = 0$, we could still say it is continuous, or continuous on its domain, correct? Since its domain doesn't include $x = 0$.

Answer 1

Yes

An example illustrating this for an isolated point is $$f(x)=\sqrt{x^4-x^2}$$ which has domain $(-\infty,-1] \cup \{0\} \cup [1, \infty)$.

This $f(x)$ is continuous on its domain according to the definition of continuity, even at the isolated point $x=0$, as there are no other points near enough to $0$ to demonstrate discontinuity

Answer 2

Yes. Since the assertion “$f$ is continuous” means “for each $a$ in the domain of $f$, $f$ is continuous at $a$”.

Answer 3

Yes, that's right. $f(x)$ is continuous on every point in its domain; there are no discontinuities where the function is defined.

Answer 4

If you define a function to be continuous iff it is continuous at every point in its domain, then yes. However, this can cause confusion. I think it's best to always specify where a function is continuous, whether it be the entire domain or some subset of it.