Is it possible to factor $4x^2-3?$
I honestly can't thing of any way to factor this, but I wanted to be sure it was, in fact, impossible to factor.
EDIT:
Thanks for the help in the comments. I realize I missed the obvious, so I'll include the answer here:
$$4x^2 - 3 = (2x-\sqrt{3})(2x+\sqrt{3})$$
$$4x^2-3=(2x-\sqrt3)(2x+\sqrt3)$$