Is it possible to factor $4x^2-3$?

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Is it possible to factor $4x^2-3?$

I honestly can't thing of any way to factor this, but I wanted to be sure it was, in fact, impossible to factor.

EDIT:

Thanks for the help in the comments. I realize I missed the obvious, so I'll include the answer here:

$$4x^2 - 3 = (2x-\sqrt{3})(2x+\sqrt{3})$$

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$$4x^2-3=(2x-\sqrt3)(2x+\sqrt3)$$

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$$4x^2-3=(2x+\sqrt3)(2x-\sqrt3)$$

It can't be factorized further, though.