Is "$k[X]^\ast= k^\ast$" preserved under finite surjective etale morphisms $Y \to X$ (for $k$ alg closed)?

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Let $k$ be an algebraically closed field of characteristic 0. Let $X$ be a smooth and connected variety over $k$, with $k[X]^\ast = k^\ast$. Suppose that $f: Y \to X$ is a surjective finite etale map of $k$-varieties, with $Y$ connected as well.

Is it true that $k[Y]^\ast = k^\ast$?

As a remark: I don't want to make properness assumptions on $X$ or $Y$ (properness would certainly imply the above).