Is $K[X]/(X^2)$ local if $K$ is a field?

Question

What I have so far is that since $K$ is a field, $K[X]$ is an integral domain and since $X^2$ is not irreducible, it is not a prime element, so $(X^2)$ is not a prime ideal, which means that $K[X]/(X^2)$ is not an integral domain. Is there a relation between integral domains and local rings (rings with exactly one maximal ideal) that can help me to conclude whether $K[X]/(X^2)$ is local or not?