I am not being able to solve this question. It is basically a high school level question and chapter I think is basic fundamentals of maths.
The value of $$\sqrt[3]{24+\sqrt[3]{24+\sqrt[3]{24+\cdots}}}$$ is equal to ...
- an even number
- a prime number
- a composite number
- an even prime number
Let us call this number X. Cubing it we have
$X^3=X+24$ so $X$ is the solution of $X^3-X-24=0$ substituting( or using Wolfram) the divisors of $24$ we have that $3$ is the only real solution.