Let $\cos z=\frac{e^{iz} - e^{-iz}}{2}$ be the complex cosine function.
Then is $\cos:\mathbb{C}\rightarrow \mathbb{C}$ surjective?
If so, how do i prove this?
Let $\cos z=\frac{e^{iz} - e^{-iz}}{2}$ be the complex cosine function.
Then is $\cos:\mathbb{C}\rightarrow \mathbb{C}$ surjective?
If so, how do i prove this?
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Hint: Do it the usual way, take an arbitrary element $w\in \mathbb C$ and try to find $z$ such that $\dfrac{e^{iz} + e^{-iz}}{2}=w$. To do this transform this equation in a polynomial of second degree on the variable $u$ with $u=e^{iz}$.