Is the delta function in $L^2$ (even though it's not a function)?

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I'm studying for a qualifying exam and in our study group someone asked the question whether the delta function is in $L^2$ spaces.

My argument is that it is; since the delta function function can be approximated by a sequence of $L^2$ functions (say, Gaussian curves with decreasing spread), and $L^2$ spaces are complete, the delta function must be included in them as well, even though the delta function is not a proper function.

This is still a question of controversy in our group, though. Is my thinking correct?

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This reasoning is not correct. If you want to use completeness, you would need that your sequence is Cauchy in $L^2$ (which it isn't). Furthermore, as you already mentioned yourself, the delta function is not a function (it is a distribution) and is therefore not in $L^2$.