I need to show whether the language $L_2$ is context-free or not where $L_2$= $\overline{L}$ such that L= { $a^nb^m$ : 0 ≤ n ≤ m ≤ 2n }.
I am able to show that L is context-free , S> aSb | aSbb | ε, but i don't know about $L_2$. Can you help me with $L_2$, thanks in advance.
2026-03-27 16:37:20.1774629440
Is the following language context-free?
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There are 2 cases for $L_2$, $m<n$ and $m>2n$ so you could make a CFG $S\rightarrow A,B$ where $A$ accomplishes the first case and $B$ accomplishes the second case.
I'll let you try to figure out the rest. If you want another hint, feel free to comment!
Edit more info:
For the first case: $m<n$
$S \rightarrow aA$
$A \rightarrow aA, aAb$
With this, you have the CFG for the language $a^nb^m, m<n$
For the second case: $m>2n$
$S \rightarrow Bb$
$B \rightarrow Bb, aBbb$
Then you combine them to get:
$S \rightarrow aA,Bb$
$A \rightarrow aA, aAb$
$B \rightarrow Bb, aBbb$