Is the following statement is true or false ?
the function $f(z) = sin z$ is not conformal on the on the infinite stripsD ={${z\in C :|Rez|< \pi}/{2}$}
i thinks this statement is true as$ f'(z) =cosz$ as $f'(z) = 0$ when$ z = \pi/{2}$
so my answer is this is true....
Pliz verifies im correct or not ?
thanks in advance....
Yes, it is conformal on that strip, since $f'(z)=\cos(z)$ and $\cos(z)\neq0$ when $|\operatorname{Re}z|<\frac\pi2$.