Is the Fourier transform of the reflection $f(-\cdot)$ equal to the reflection of the Fourier transform?

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Suppose that the reflection operator $A:L^2(\mathbb R) \to L^2(\mathbb R)$ is defined as $Af(x)=f(-x)$. Let $F : L^2(\mathbb R) \to L^2(\mathbb R)$ be the Fourier transform. Is it true that $A$ commutes with $F$?