Is the norm of a vector given by dividing it by the square root of the inner product with itself?

288 Views Asked by At

I've known the norm (aka. unit vector in the direction of) a vector (let's call it $v$) to be given by the formula: $v/\sqrt{v \cdot v}$, where $\cdot$ is the dot product.

But can this be generalized to inner products, such that the norm the norm of a vector can be found by $v/\sqrt{< v,v>}$, where $<v,v>$ is the vector's inner product with itself? (since the dot product is an inner product this definition would agree with the previous one)

Any help is appreciated.